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X+3=2/5X-1
We move all terms to the left:
X+3-(2/5X-1)=0
Domain of the equation: 5X-1)!=0We get rid of parentheses
X∈R
X-2/5X+1+3=0
We multiply all the terms by the denominator
X*5X+1*5X+3*5X-2=0
Wy multiply elements
5X^2+5X+15X-2=0
We add all the numbers together, and all the variables
5X^2+20X-2=0
a = 5; b = 20; c = -2;
Δ = b2-4ac
Δ = 202-4·5·(-2)
Δ = 440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{440}=\sqrt{4*110}=\sqrt{4}*\sqrt{110}=2\sqrt{110}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{110}}{2*5}=\frac{-20-2\sqrt{110}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{110}}{2*5}=\frac{-20+2\sqrt{110}}{10} $
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