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400=x2+30x
We move all terms to the left:
400-(x2+30x)=0
We add all the numbers together, and all the variables
-(+x^2+30x)+400=0
We get rid of parentheses
-x^2-30x+400=0
We add all the numbers together, and all the variables
-1x^2-30x+400=0
a = -1; b = -30; c = +400;
Δ = b2-4ac
Δ = -302-4·(-1)·400
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-50}{2*-1}=\frac{-20}{-2} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+50}{2*-1}=\frac{80}{-2} =-40 $
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