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2/3b-1/6b=75
We move all terms to the left:
2/3b-1/6b-(75)=0
Domain of the equation: 3b!=0
b!=0/3
b!=0
b∈R
Domain of the equation: 6b!=0We calculate fractions
b!=0/6
b!=0
b∈R
12b/18b^2+(-3b)/18b^2-75=0
We multiply all the terms by the denominator
12b+(-3b)-75*18b^2=0
Wy multiply elements
-1350b^2+12b+(-3b)=0
We get rid of parentheses
-1350b^2+12b-3b=0
We add all the numbers together, and all the variables
-1350b^2+9b=0
a = -1350; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-1350)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-1350}=\frac{-18}{-2700} =1/150 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-1350}=\frac{0}{-2700} =0 $
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