40-5(8+2y)=2

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Solution for 40-5(8+2y)=2 equation: 



40-5(8+2y)=2

We move all terms to the left:

40-5(8+2y)-(2)=0

We add all the numbers together, and all the variables

-5(2y+8)+40-2=0

We add all the numbers together, and all the variables

-5(2y+8)+38=0

We multiply parentheses

-10y-40+38=0

We add all the numbers together, and all the variables

-10y-2=0

We move all terms containing y to the left, all other terms to the right

-10y=2

y=2/-10

y=-1/5

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