1/8f-3/4-1/4f=11

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Solution for 1/8f-3/4-1/4f=11 equation:



1/8f-3/4-1/4f=11
We move all terms to the left:
1/8f-3/4-1/4f-(11)=0
Domain of the equation: 8f!=0
f!=0/8
f!=0
f∈R
Domain of the equation: 4f!=0
f!=0/4
f!=0
f∈R
determiningTheFunctionDomain 1/8f-1/4f-11-3/4=0
We calculate fractions
64f/512f^2+(-8f)/512f^2+(-24f)/512f^2-11=0
We multiply all the terms by the denominator
64f+(-8f)+(-24f)-11*512f^2=0
Wy multiply elements
-5632f^2+64f+(-8f)+(-24f)=0
We get rid of parentheses
-5632f^2+64f-8f-24f=0
We add all the numbers together, and all the variables
-5632f^2+32f=0
a = -5632; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·(-5632)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*-5632}=\frac{-64}{-11264} =1/176 $
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*-5632}=\frac{0}{-11264} =0 $

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