40+4x=3(-x+6)-20

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Solution for 40+4x=3(-x+6)-20 equation: 



40+4x=3(-x+6)-20

We move all terms to the left:

40+4x-(3(-x+6)-20)=0

We add all the numbers together, and all the variables

4x-(3(-1x+6)-20)+40=0



We calculate terms in parentheses: -(3(-1x+6)-20), so:

3(-1x+6)-20

We multiply parentheses

-3x+18-20

We add all the numbers together, and all the variables

-3x-2

Back to the equation:

-(-3x-2)



We get rid of parentheses

4x+3x+2+40=0

We add all the numbers together, and all the variables

7x+42=0

We move all terms containing x to the left, all other terms to the right

7x=-42

x=-42/7

x=-6

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