3x2+18x+64=2x2+2x

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Solution for 3x2+18x+64=2x2+2x equation: 



3x^2+18x+64=2x^2+2x

We move all terms to the left:

3x^2+18x+64-(2x^2+2x)=0

We get rid of parentheses

3x^2-2x^2+18x-2x+64=0

We add all the numbers together, and all the variables

x^2+16x+64=0

a = 1; b = 16; c = +64;
Δ = b2-4ac
Δ = 162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{2}=-8$

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