40+4x=100+2x2

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Solution for 40+4x=100+2x2 equation: 



40+4x=100+2x^2

We move all terms to the left:

40+4x-(100+2x^2)=0

We get rid of parentheses

-2x^2+4x-100+40=0

We add all the numbers together, and all the variables

-2x^2+4x-60=0

a = -2; b = 4; c = -60;
Δ = b2-4ac
Δ = 42-4·(-2)·(-60)
Δ = -464
Delta is less than zero, so there is no solution for the equation

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