2(x-4)+8x=1

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Solution for 2(x-4)+8x=1 equation: 



2(x-4)+8x=1

We move all terms to the left:

2(x-4)+8x-(1)=0

We add all the numbers together, and all the variables

8x+2(x-4)-1=0

We multiply parentheses

8x+2x-8-1=0

We add all the numbers together, and all the variables

10x-9=0

We move all terms containing x to the left, all other terms to the right

10x=9

x=9/10

x=9/10

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