40+3x=-8(-2x-8)-x

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Solution for 40+3x=-8(-2x-8)-x equation: 



40+3x=-8(-2x-8)-x

We move all terms to the left:

40+3x-(-8(-2x-8)-x)=0



We calculate terms in parentheses: -(-8(-2x-8)-x), so:

-8(-2x-8)-x

We add all the numbers together, and all the variables

-1x-8(-2x-8)

We multiply parentheses

-1x+16x+64

We add all the numbers together, and all the variables

15x+64

Back to the equation:

-(15x+64)



We get rid of parentheses

3x-15x-64+40=0

We add all the numbers together, and all the variables

-12x-24=0

We move all terms containing x to the left, all other terms to the right

-12x=24

x=24/-12

x=-2

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