7-(1/4)8-6x)=(4/5)(2x+10)-3

Solution for 7-(1/4)8-6x)=(4/5)(2x+10)-3 equation:

7-(1/4)8-6x)=(4/5)(2x+10)-3

We move all terms to the left:

7-(1/4)8-6x)-((4/5)(2x+10)-3)=0


Domain of the equation: 5)(2x+10)!=0

x∈R


We add all the numbers together, and all the variables

-6x)-((+4/5)(2x+10)+7-(+1/4)8-3)=0

We add all the numbers together, and all the variables

-6x)-((+4/5)(2x+10)-(+1/4)8=0

We multiply parentheses

-6x)-((+4/5)(2x+10)-1/4*8=0

We multiply parentheses ..

-6x)-((+8x^2+4/5*10)-1/4*8=0

We calculate fractions


-((+8x^2+4*4*8)/()+()/()+(-6x)=0


We calculate terms in parentheses: -((+8x^2+4*4*8)/()+()/()+(-6x), so:

(+8x^2+4*4*8)/()+()/()+(-6x

determiningTheFunctionDomain
(+8x^2+4*4*8)/()+(-6x+()/()

We multiply all the terms by the denominator


(+8x^2+4*4*8)+(-6x+()


We calculate terms in parentheses: +(-6x+(), so:

-6x+(

We add all the numbers together, and all the variables

-6x

Back to the equation:

+(-6x)


We get rid of parentheses

8x^2-6x+4*4*8

We add all the numbers together, and all the variables

8x^2-6x+128

Back to the equation:

-(8x^2-6x+128)


We get rid of parentheses

-8x^2+6x-128=0

a = -8; b = 6; c = -128;
Δ = b2-4ac
Δ = 62-4·(-8)·(-128)
Δ = -4060
Delta is less than zero, so there is no solution for the equation