40+3n=6+2(5n+3)

Solution for 40+3n=6+2(5n+3) equation:

40+3n=6+2(5n+3)

We move all terms to the left:

40+3n-(6+2(5n+3))=0


We calculate terms in parentheses: -(6+2(5n+3)), so:

6+2(5n+3)

determiningTheFunctionDomain
2(5n+3)+6

We multiply parentheses

10n+6+6

We add all the numbers together, and all the variables

10n+12

Back to the equation:

-(10n+12)


We get rid of parentheses

3n-10n-12+40=0

We add all the numbers together, and all the variables

-7n+28=0

We move all terms containing n to the left, all other terms to the right

-7n=-28

n=-28/-7

n=+4