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3(x+5)=2(x+2)
We move all terms to the left:
3(x+5)-(2(x+2))=0
We multiply parentheses
3x-(2(x+2))+15=0
We calculate terms in parentheses: -(2(x+2)), so:We get rid of parentheses
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
3x-2x-4+15=0
We add all the numbers together, and all the variables
x+11=0
We move all terms containing x to the left, all other terms to the right
x=-11
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