40+3b=5(3b-4)

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Solution for 40+3b=5(3b-4) equation: 



40+3b=5(3b-4)

We move all terms to the left:

40+3b-(5(3b-4))=0



We calculate terms in parentheses: -(5(3b-4)), so:

5(3b-4)

We multiply parentheses

15b-20

Back to the equation:

-(15b-20)



We get rid of parentheses

3b-15b+20+40=0

We add all the numbers together, and all the variables

-12b+60=0

We move all terms containing b to the left, all other terms to the right

-12b=-60

b=-60/-12

b=+5

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