-(m-1)=-(1+3m)+8

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Solution for -(m-1)=-(1+3m)+8 equation: 



-(m-1)=-(1+3m)+8

We move all terms to the left:

-(m-1)-(-(1+3m)+8)=0

We add all the numbers together, and all the variables

-(m-1)-(-(3m+1)+8)=0

We get rid of parentheses

-m-(-(3m+1)+8)+1=0



We calculate terms in parentheses: -(-(3m+1)+8), so:

-(3m+1)+8

We get rid of parentheses

-3m-1+8

We add all the numbers together, and all the variables

-3m+7

Back to the equation:

-(-3m+7)



We add all the numbers together, and all the variables

-1m-(-3m+7)+1=0

We get rid of parentheses

-1m+3m-7+1=0

We add all the numbers together, and all the variables

2m-6=0

We move all terms containing m to the left, all other terms to the right

2m=6

m=6/2

m=3

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