40+3(x+3)-6=-5(x-12)+16

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Solution for 40+3(x+3)-6=-5(x-12)+16 equation: 



40+3(x+3)-6=-5(x-12)+16

We move all terms to the left:

40+3(x+3)-6-(-5(x-12)+16)=0

We add all the numbers together, and all the variables

3(x+3)-(-5(x-12)+16)+34=0

We multiply parentheses

3x-(-5(x-12)+16)+9+34=0



We calculate terms in parentheses: -(-5(x-12)+16), so:

-5(x-12)+16

We multiply parentheses

-5x+60+16

We add all the numbers together, and all the variables

-5x+76

Back to the equation:

-(-5x+76)



We add all the numbers together, and all the variables

3x-(-5x+76)+43=0

We get rid of parentheses

3x+5x-76+43=0

We add all the numbers together, and all the variables

8x-33=0

We move all terms containing x to the left, all other terms to the right

8x=33

x=33/8

x=4+1/8

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