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2/7x+5=3/8x
We move all terms to the left:
2/7x+5-(3/8x)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 8x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/7x-(+3/8x)+5=0
We get rid of parentheses
2/7x-3/8x+5=0
We calculate fractions
16x/56x^2+(-21x)/56x^2+5=0
We multiply all the terms by the denominator
16x+(-21x)+5*56x^2=0
Wy multiply elements
280x^2+16x+(-21x)=0
We get rid of parentheses
280x^2+16x-21x=0
We add all the numbers together, and all the variables
280x^2-5x=0
a = 280; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·280·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*280}=\frac{0}{560} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*280}=\frac{10}{560} =1/56 $
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