40(x-4)=8(10x-15)

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Solution for 40(x-4)=8(10x-15) equation:


Simplifying
40(x + -4) = 8(10x + -15)

Reorder the terms:
40(-4 + x) = 8(10x + -15)
(-4 * 40 + x * 40) = 8(10x + -15)
(-160 + 40x) = 8(10x + -15)

Reorder the terms:
-160 + 40x = 8(-15 + 10x)
-160 + 40x = (-15 * 8 + 10x * 8)
-160 + 40x = (-120 + 80x)

Solving
-160 + 40x = -120 + 80x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-80x' to each side of the equation.
-160 + 40x + -80x = -120 + 80x + -80x

Combine like terms: 40x + -80x = -40x
-160 + -40x = -120 + 80x + -80x

Combine like terms: 80x + -80x = 0
-160 + -40x = -120 + 0
-160 + -40x = -120

Add '160' to each side of the equation.
-160 + 160 + -40x = -120 + 160

Combine like terms: -160 + 160 = 0
0 + -40x = -120 + 160
-40x = -120 + 160

Combine like terms: -120 + 160 = 40
-40x = 40

Divide each side by '-40'.
x = -1

Simplifying
x = -1

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