1/3k-(k+1/2)=1/6(k+2)

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Solution for 1/3k-(k+1/2)=1/6(k+2) equation: 


k in (-oo:+oo)

(1/3)*k-k-(1/2) = (1/6)*(k+2) // - (1/6)*(k+2)

(1/3)*k-((1/6)*(k+2))-k-(1/2) = 0

(-1/6)*(k+2)+(1/3)*k-k-1/2 = 0

k/3-1/6*(k+2)-k-1/2 = 0

(-1/6*2*3*(k+2))/(2*3)+(2*k)/(2*3)+(2*3*(-k))/(2*3)+(-1*3)/(2*3) = 0

2*k-1/6*2*3*(k+2)+2*3*(-k)-1*3 = 0

k-6*k-3-2 = 0

-5*k-3-2 = 0

-5*k-5 = 0

(-5*k-5)/(2*3) = 0

(-5*k-5)/(2*3) = 0 // * 2*3

-5*k-5 = 0

-5*k-5 = 0 // + 5

-5*k = 5 // : -5

k = 5/(-5)

k = -1

k = -1

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