4/7x+5/15x=39

Solution for 4/7x+5/15x=39 equation:

4/7x+5/15x=39

We move all terms to the left:

4/7x+5/15x-(39)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 15x!=0

x!=0/15

x!=0

x∈R


We calculate fractions


60x/105x^2+35x/105x^2-39=0

We multiply all the terms by the denominator


60x+35x-39*105x^2=0

We add all the numbers together, and all the variables

95x-39*105x^2=0

Wy multiply elements

-4095x^2+95x=0

a = -4095; b = 95; c = 0;
Δ = b2-4ac
Δ = 952-4·(-4095)·0
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-95}{2*-4095}=\frac{-190}{-8190}
=19/819
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+95}{2*-4095}=\frac{0}{-8190}
=0
$