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(v+15)+8v(v+15)=180
We move all terms to the left:
(v+15)+8v(v+15)-(180)=0
We multiply parentheses
8v^2+(v+15)+120v-180=0
We get rid of parentheses
8v^2+v+120v+15-180=0
We add all the numbers together, and all the variables
8v^2+121v-165=0
a = 8; b = 121; c = -165;
Δ = b2-4ac
Δ = 1212-4·8·(-165)
Δ = 19921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(121)-\sqrt{19921}}{2*8}=\frac{-121-\sqrt{19921}}{16} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(121)+\sqrt{19921}}{2*8}=\frac{-121+\sqrt{19921}}{16} $
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