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4/5x^2=6
We move all terms to the left:
4/5x^2-(6)=0
Domain of the equation: 5x^2!=0We multiply all the terms by the denominator
x^2!=0/5
x^2!=√0
x!=0
x∈R
-6*5x^2+4=0
Wy multiply elements
-30x^2+4=0
a = -30; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-30)·4
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*-30}=\frac{0-4\sqrt{30}}{-60} =-\frac{4\sqrt{30}}{-60} =-\frac{\sqrt{30}}{-15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*-30}=\frac{0+4\sqrt{30}}{-60} =\frac{4\sqrt{30}}{-60} =\frac{\sqrt{30}}{-15} $
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