4(x+3)=-3(4x-2)+7x

Solution for 4(x+3)=-3(4x-2)+7x equation:

4(x+3)=-3(4x-2)+7x

We move all terms to the left:

4(x+3)-(-3(4x-2)+7x)=0

We multiply parentheses

4x-(-3(4x-2)+7x)+12=0


We calculate terms in parentheses: -(-3(4x-2)+7x), so:

-3(4x-2)+7x

We add all the numbers together, and all the variables

7x-3(4x-2)

We multiply parentheses

7x-12x+6

We add all the numbers together, and all the variables

-5x+6

Back to the equation:

-(-5x+6)


We get rid of parentheses

4x+5x-6+12=0

We add all the numbers together, and all the variables

9x+6=0

We move all terms containing x to the left, all other terms to the right

9x=-6

x=-6/9

x=-2/3