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4/5x-4=-9/10x+1
We move all terms to the left:
4/5x-4-(-9/10x+1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x+1)!=0We get rid of parentheses
x∈R
4/5x+9/10x-1-4=0
We calculate fractions
40x/50x^2+45x/50x^2-1-4=0
We add all the numbers together, and all the variables
40x/50x^2+45x/50x^2-5=0
We multiply all the terms by the denominator
40x+45x-5*50x^2=0
We add all the numbers together, and all the variables
85x-5*50x^2=0
Wy multiply elements
-250x^2+85x=0
a = -250; b = 85; c = 0;
Δ = b2-4ac
Δ = 852-4·(-250)·0
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-85}{2*-250}=\frac{-170}{-500} =17/50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+85}{2*-250}=\frac{0}{-500} =0 $
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