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4/5x-1.4x=11
We move all terms to the left:
4/5x-1.4x-(11)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-1.4x+4/5x-11=0
We multiply all the terms by the denominator
-(1.4x)*5x-11*5x+4=0
We add all the numbers together, and all the variables
-(+1.4x)*5x-11*5x+4=0
We multiply parentheses
-5x^2-11*5x+4=0
Wy multiply elements
-5x^2-55x+4=0
a = -5; b = -55; c = +4;
Δ = b2-4ac
Δ = -552-4·(-5)·4
Δ = 3105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3105}=\sqrt{9*345}=\sqrt{9}*\sqrt{345}=3\sqrt{345}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-3\sqrt{345}}{2*-5}=\frac{55-3\sqrt{345}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+3\sqrt{345}}{2*-5}=\frac{55+3\sqrt{345}}{-10} $
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