4/5x+7=2x+2

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Solution for 4/5x+7=2x+2 equation:



4/5x+7=2x+2
We move all terms to the left:
4/5x+7-(2x+2)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
We get rid of parentheses
4/5x-2x-2+7=0
We multiply all the terms by the denominator
-2x*5x-2*5x+7*5x+4=0
Wy multiply elements
-10x^2-10x+35x+4=0
We add all the numbers together, and all the variables
-10x^2+25x+4=0
a = -10; b = 25; c = +4;
Δ = b2-4ac
Δ = 252-4·(-10)·4
Δ = 785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{785}}{2*-10}=\frac{-25-\sqrt{785}}{-20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{785}}{2*-10}=\frac{-25+\sqrt{785}}{-20} $

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