-5(x+6)+3(2x-5)=3(x-4)+10

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Solution for -5(x+6)+3(2x-5)=3(x-4)+10 equation: 



-5(x+6)+3(2x-5)=3(x-4)+10

We move all terms to the left:

-5(x+6)+3(2x-5)-(3(x-4)+10)=0

We multiply parentheses

-5x+6x-(3(x-4)+10)-30-15=0



We calculate terms in parentheses: -(3(x-4)+10), so:

3(x-4)+10

We multiply parentheses

3x-12+10

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

x-(3x-2)-45=0

We get rid of parentheses

x-3x+2-45=0

We add all the numbers together, and all the variables

-2x-43=0

We move all terms containing x to the left, all other terms to the right

-2x=43

x=43/-2

x=-21+1/2

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