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4/5m-7=1/10m
We move all terms to the left:
4/5m-7-(1/10m)=0
Domain of the equation: 5m!=0
m!=0/5
m!=0
m∈R
Domain of the equation: 10m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
4/5m-(+1/10m)-7=0
We get rid of parentheses
4/5m-1/10m-7=0
We calculate fractions
40m/50m^2+(-5m)/50m^2-7=0
We multiply all the terms by the denominator
40m+(-5m)-7*50m^2=0
Wy multiply elements
-350m^2+40m+(-5m)=0
We get rid of parentheses
-350m^2+40m-5m=0
We add all the numbers together, and all the variables
-350m^2+35m=0
a = -350; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·(-350)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*-350}=\frac{-70}{-700} =1/10 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*-350}=\frac{0}{-700} =0 $
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