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(1/5m)+(2/5-2)=m-2/5
We move all terms to the left:
(1/5m)+(2/5-2)-(m-2/5)=0
Domain of the equation: 5m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
(+1/5m)-(+m-2/5)+(2/5-2)=0
We get rid of parentheses
1/5m-m-2+2/5+2/5=0
We calculate fractions
-m-2=0
We add all the numbers together, and all the variables
-1m-2=0
We move all terms containing m to the left, all other terms to the right
-m=2
m=2/-1
m=-2
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