4/5f=28

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Solution for 4/5f=28 equation: 



4/5f=28

We move all terms to the left:

4/5f-(28)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R



We multiply all the terms by the denominator


-28*5f+4=0

Wy multiply elements

-140f+4=0

We move all terms containing f to the left, all other terms to the right

-140f=-4

f=-4/-140

f=1/35

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