(2y+6)=(y-4)/3

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Solution for (2y+6)=(y-4)/3 equation: 



(2y+6)=(y-4)/3

We move all terms to the left:

(2y+6)-((y-4)/3)=0

We get rid of parentheses

2y-((y-4)/3)+6=0

We multiply all the terms by the denominator


2y*3)-((y-4)+6*3)=0

We add all the numbers together, and all the variables

2y*3)-((y-4)=0

Wy multiply elements

6y^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{12}=0$

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