4/5(x+3)=6+2/7x

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Solution for 4/5(x+3)=6+2/7x equation: 



4/5(x+3)=6+2/7x

We move all terms to the left:

4/5(x+3)-(6+2/7x)=0



Domain of the equation: 5(x+3)!=0

x∈R





Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4/5(x+3)-(2/7x+6)=0

We get rid of parentheses

4/5(x+3)-2/7x-6=0

We calculate fractions


28x/(35x^2+105x)+(-10xx/(35x^2+105x)-6=0

We calculate fractions

We do not support expression: x^3

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