4/5(5x+2)=x+35

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Solution for 4/5(5x+2)=x+35 equation: 



4/5(5x+2)=x+35

We move all terms to the left:

4/5(5x+2)-(x+35)=0



Domain of the equation: 5(5x+2)!=0

x∈R



We get rid of parentheses

4/5(5x+2)-x-35=0

We multiply all the terms by the denominator


-x*5(5x+2)-35*5(5x+2)+4=0

Wy multiply elements

-5x^2(5-175x(5+4=0

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