4x2-16x+16=0

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Solution for 4x2-16x+16=0 equation: 



4x^2-16x+16=0

a = 4; b = -16; c = +16;
Δ = b2-4ac
Δ = -162-4·4·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{8}=2$

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