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4/3x-1/2x=25
We move all terms to the left:
4/3x-1/2x-(25)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
8x/6x^2+(-3x)/6x^2-25=0
We multiply all the terms by the denominator
8x+(-3x)-25*6x^2=0
Wy multiply elements
-150x^2+8x+(-3x)=0
We get rid of parentheses
-150x^2+8x-3x=0
We add all the numbers together, and all the variables
-150x^2+5x=0
a = -150; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-150)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-150}=\frac{-10}{-300} =1/30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-150}=\frac{0}{-300} =0 $
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