6(x+4)-8=4(x+4)+2x

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Solution for 6(x+4)-8=4(x+4)+2x equation: 



6(x+4)-8=4(x+4)+2x

We move all terms to the left:

6(x+4)-8-(4(x+4)+2x)=0

We multiply parentheses

6x-(4(x+4)+2x)+24-8=0



We calculate terms in parentheses: -(4(x+4)+2x), so:

4(x+4)+2x

We add all the numbers together, and all the variables

2x+4(x+4)

We multiply parentheses

2x+4x+16

We add all the numbers together, and all the variables

6x+16

Back to the equation:

-(6x+16)



We add all the numbers together, and all the variables

6x-(6x+16)+16=0

We get rid of parentheses

6x-6x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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