4/(2x-3)=(2/(3x+1))+2

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Solution for 4/(2x-3)=(2/(3x+1))+2 equation: 



4/(2x-3)=(2/(3x+1))+2

We move all terms to the left:

4/(2x-3)-((2/(3x+1))+2)=0



Domain of the equation: (2x-3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=3

x!=3/2

x!=1+1/2

x∈R





Domain of the equation: (3x+1))+2)!=0

x∈R



We calculate fractions


12x/((2x-3)*(3x+1))+2))+(-((2*(2x-3))/((2x-3)*(3x+1))+2))=0

We add all the numbers together, and all the variables

12x/((2x-3)*(3x+1))+2))+(-((2*(2x-3))/((2x-3)*(3x+1))=0

We multiply all the terms by the denominator


12x+2))+(-((2*(2x-3))=0

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