27(a-4)=4a-(2a+4)

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Solution for 27(a-4)=4a-(2a+4) equation: 



27(a-4)=4a-(2a+4)

We move all terms to the left:

27(a-4)-(4a-(2a+4))=0

We multiply parentheses

27a-(4a-(2a+4))-108=0



We calculate terms in parentheses: -(4a-(2a+4)), so:

4a-(2a+4)

We get rid of parentheses

4a-2a-4

We add all the numbers together, and all the variables

2a-4

Back to the equation:

-(2a-4)



We get rid of parentheses

27a-2a+4-108=0

We add all the numbers together, and all the variables

25a-104=0

We move all terms containing a to the left, all other terms to the right

25a=104

a=104/25

a=4+4/25

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