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4.9x^2-29.59x+2=0
a = 4.9; b = -29.59; c = +2;
Δ = b2-4ac
Δ = -29.592-4·4.9·2
Δ = 836.3681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29.59)-\sqrt{836.3681}}{2*4.9}=\frac{29.59-\sqrt{836.3681}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29.59)+\sqrt{836.3681}}{2*4.9}=\frac{29.59+\sqrt{836.3681}}{9.8} $
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