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4.9x^2-22.5x+8=0
a = 4.9; b = -22.5; c = +8;
Δ = b2-4ac
Δ = -22.52-4·4.9·8
Δ = 349.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22.5)-\sqrt{349.45}}{2*4.9}=\frac{22.5-\sqrt{349.45}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22.5)+\sqrt{349.45}}{2*4.9}=\frac{22.5+\sqrt{349.45}}{9.8} $
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