4.2n2+6.3+9n-5.8-2n+n2=

Solution for 4.2n2+6.3+9n-5.8-2n+n2= equation:

4.2n^2+6.3+9n-5.8-2n+n2=

We move all terms to the left:

4.2n^2+6.3+9n-5.8-2n+n2-()=0

We add all the numbers together, and all the variables

5.2n^2+7n=0

a = 5.2; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·5.2·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*5.2}=\frac{-14}{10.4}
=-1+2.25/6.5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*5.2}=\frac{0}{10.4}
=0
$