(12-8x)+2x=4x+15-(x+3)

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Solution for (12-8x)+2x=4x+15-(x+3) equation: 



(12-8x)+2x=4x+15-(x+3)

We move all terms to the left:

(12-8x)+2x-(4x+15-(x+3))=0

We add all the numbers together, and all the variables

(-8x+12)+2x-(4x+15-(x+3))=0

We add all the numbers together, and all the variables

2x+(-8x+12)-(4x+15-(x+3))=0

We get rid of parentheses

2x-8x-(4x+15-(x+3))+12=0



We calculate terms in parentheses: -(4x+15-(x+3)), so:

4x+15-(x+3)

determiningTheFunctionDomain
4x-(x+3)+15

We get rid of parentheses

4x-x-3+15

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

-6x-(3x+12)+12=0

We get rid of parentheses

-6x-3x-12+12=0

We add all the numbers together, and all the variables

-9x=0

x=0/-9

x=0

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