4-5(3-x)+2x=8-2(x-3)

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Solution for 4-5(3-x)+2x=8-2(x-3) equation: 



4-5(3-x)+2x=8-2(x-3)

We move all terms to the left:

4-5(3-x)+2x-(8-2(x-3))=0

We add all the numbers together, and all the variables

-5(-1x+3)+2x-(8-2(x-3))+4=0

We add all the numbers together, and all the variables

2x-5(-1x+3)-(8-2(x-3))+4=0

We multiply parentheses

2x+5x-(8-2(x-3))-15+4=0



We calculate terms in parentheses: -(8-2(x-3)), so:

8-2(x-3)

determiningTheFunctionDomain
-2(x-3)+8

We multiply parentheses

-2x+6+8

We add all the numbers together, and all the variables

-2x+14

Back to the equation:

-(-2x+14)



We add all the numbers together, and all the variables

7x-(-2x+14)-11=0

We get rid of parentheses

7x+2x-14-11=0

We add all the numbers together, and all the variables

9x-25=0

We move all terms containing x to the left, all other terms to the right

9x=25

x=25/9

x=2+7/9

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