(3-2x)-(x+4)-(x+4)-(2x+5)=(3x-4)-(5x+7)

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Solution for (3-2x)-(x+4)-(x+4)-(2x+5)=(3x-4)-(5x+7) equation: 



(3-2x)-(x+4)-(x+4)-(2x+5)=(3x-4)-(5x+7)

We move all terms to the left:

(3-2x)-(x+4)-(x+4)-(2x+5)-((3x-4)-(5x+7))=0

We add all the numbers together, and all the variables

(-2x+3)-(x+4)-(x+4)-(2x+5)-((3x-4)-(5x+7))=0

We get rid of parentheses

-2x-x-x-2x-((3x-4)-(5x+7))+3-4-4-5=0



We calculate terms in parentheses: -((3x-4)-(5x+7)), so:

(3x-4)-(5x+7)

We get rid of parentheses

3x-5x-4-7

We add all the numbers together, and all the variables

-2x-11

Back to the equation:

-(-2x-11)



We add all the numbers together, and all the variables

-6x-(-2x-11)-10=0

We get rid of parentheses

-6x+2x+11-10=0

We add all the numbers together, and all the variables

-4x+1=0

We move all terms containing x to the left, all other terms to the right

-4x=-1

x=-1/-4

x=1/4

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