4-3x+2+2x=-4(6x-4)+3(7x+2)

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Solution for 4-3x+2+2x=-4(6x-4)+3(7x+2) equation: 



4-3x+2+2x=-4(6x-4)+3(7x+2)

We move all terms to the left:

4-3x+2+2x-(-4(6x-4)+3(7x+2))=0

We add all the numbers together, and all the variables

-1x-(-4(6x-4)+3(7x+2))+6=0



We calculate terms in parentheses: -(-4(6x-4)+3(7x+2)), so:

-4(6x-4)+3(7x+2)

We multiply parentheses

-24x+21x+16+6

We add all the numbers together, and all the variables

-3x+22

Back to the equation:

-(-3x+22)



We get rid of parentheses

-1x+3x-22+6=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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