6(u+2)=-2(4u-3)+2u

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Solution for 6(u+2)=-2(4u-3)+2u equation: 



6(u+2)=-2(4u-3)+2u

We move all terms to the left:

6(u+2)-(-2(4u-3)+2u)=0

We multiply parentheses

6u-(-2(4u-3)+2u)+12=0



We calculate terms in parentheses: -(-2(4u-3)+2u), so:

-2(4u-3)+2u

We add all the numbers together, and all the variables

2u-2(4u-3)

We multiply parentheses

2u-8u+6

We add all the numbers together, and all the variables

-6u+6

Back to the equation:

-(-6u+6)



We get rid of parentheses

6u+6u-6+12=0

We add all the numbers together, and all the variables

12u+6=0

We move all terms containing u to the left, all other terms to the right

12u=-6

u=-6/12

u=-1/2

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