4-3(x+2)=6-2(x-3)

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Solution for 4-3(x+2)=6-2(x-3) equation: 



4-3(x+2)=6-2(x-3)

We move all terms to the left:

4-3(x+2)-(6-2(x-3))=0

We multiply parentheses

-3x-(6-2(x-3))-6+4=0



We calculate terms in parentheses: -(6-2(x-3)), so:

6-2(x-3)

determiningTheFunctionDomain
-2(x-3)+6

We multiply parentheses

-2x+6+6

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We add all the numbers together, and all the variables

-3x-(-2x+12)-2=0

We get rid of parentheses

-3x+2x-12-2=0

We add all the numbers together, and all the variables

-1x-14=0

We move all terms containing x to the left, all other terms to the right

-x=14

x=14/-1

x=-14

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