12-(3x2)=(12-3)x2

Solution for 12-(3x2)=(12-3)x2 equation:

12-(3x^2)=(12-3)x2

We move all terms to the left:

12-(3x^2)-((12-3)x2)=0

We add all the numbers together, and all the variables

-3x^2-(9x2)+12=0

We add all the numbers together, and all the variables

-12x^2+12=0

a = -12; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-12)·12
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-12}=\frac{-24}{-24}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-12}=\frac{24}{-24}
=-1
$