4-3(2g+1)+4g=9(g-3)-5

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Solution for 4-3(2g+1)+4g=9(g-3)-5 equation: 



4-3(2g+1)+4g=9(g-3)-5

We move all terms to the left:

4-3(2g+1)+4g-(9(g-3)-5)=0

We add all the numbers together, and all the variables

4g-3(2g+1)-(9(g-3)-5)+4=0

We multiply parentheses

4g-6g-(9(g-3)-5)-3+4=0



We calculate terms in parentheses: -(9(g-3)-5), so:

9(g-3)-5

We multiply parentheses

9g-27-5

We add all the numbers together, and all the variables

9g-32

Back to the equation:

-(9g-32)



We add all the numbers together, and all the variables

-2g-(9g-32)+1=0

We get rid of parentheses

-2g-9g+32+1=0

We add all the numbers together, and all the variables

-11g+33=0

We move all terms containing g to the left, all other terms to the right

-11g=-33

g=-33/-11

g=+3

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