3(x-4)=2(-3x+1)

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Solution for 3(x-4)=2(-3x+1) equation: 



3(x-4)=2(-3x+1)

We move all terms to the left:

3(x-4)-(2(-3x+1))=0

We multiply parentheses

3x-(2(-3x+1))-12=0



We calculate terms in parentheses: -(2(-3x+1)), so:

2(-3x+1)

We multiply parentheses

-6x+2

Back to the equation:

-(-6x+2)



We get rid of parentheses

3x+6x-2-12=0

We add all the numbers together, and all the variables

9x-14=0

We move all terms containing x to the left, all other terms to the right

9x=14

x=14/9

x=1+5/9

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